对数与对数的运算练习题.docx

对数与对数运算练习题一.选择题1. 2一3=/化为对数式为（）A.B嵋(-3)=2C.Iog2=-3D.Iog2(-3)=2. Iog63+1og62等于(A.6B.5C.1D.Iog53.如果IgX=Ig+21gZ?-31gc,则X等于()A.a+2b3cB.a+tr-ci4.已知d=1og32,那么1og38-21ogj6用a表示为()A.。-2C.3a-(1÷a)25.2,+5的值等于()B.5a2D.3。一。2一1A.2+5c2+当6. 1og25的值为(A.-2C.-2B.2D.；7.在人=1og）（5-）中，实数。的取值范围是（）A.a>5或a<2B.2VV3或3VV5C.2<a<5D.3<a<48.方程233=;的解是（）=苴a3C.x=y3D.x=99. Iog2(1og3)=Iog3(1og4y)=Iog4(1og2z)=0,则%+y+z的值为()A.9B.8C.7D.610 .若102=25,则X等于()A.1gB.Ig5C.21g5D.21g11 .计算Iog891og932的结果为()5C1A.4B.gC.dI12.已知IOgar=2,1ogk=1,1ogcx=4(,b,ax>0且HI),贝J1og(M?C)/(=4-7A.2-7B7-2C7-4D二.填空题1 .21og510+1og50.25=.2 .方程1og3(2x1)=1的解为X=.3 .若Ig(InX)=0,则X=.4 .方程9A63A7=0的解是5 .若1。834108481088加=108416,贝IJm=.6 .已知Ioga2=m,1gG3=",则k)g"18=.(用Am表示)7 .Iog61og4(1og381)=.8 .使对数式1og(.v-1)(3x)有意义的X的取值范围是三.计算题1.计算：;1g1.2(I)21og210+1og2.04(3)1og6j-21og63+1og627(4)1og2(3+2)+1og2(23):2.已知Iog341og48k)g8m=k)g416,求？的值.对数与对数运算练习题答案一.选择题1. C2.C3.C4.A5.B6.D7.B8A9.A10.B11.B12.D二.填空题1.22.23.e4.x=1og375. 96.tn+2n7.08.1<v<3fix2.计算题1 .解：(I)21og210÷1og2.04=10g2(100×0.04)=1og24=2Ig3+21g2-11g(3X4÷X)1g1.21Ig1.2Ig1.2-1g1.21(3)1og6*一21og3÷1og627=1og6-1og9+IogQ=1og6(×I×3)=1g6=-2.(4)1og2(3÷2)÷1og2(2-3)=1og2(2÷3)(2-3)=10g21=0.2 .解析1og416=2,Iog341og481og8n=10g3w=2,=9.