路易实操翻模问题立交20230224.docx
-13871984474628.376706.6813872151473948.30836.662500836.66013871853472475.20994.9873000994.987013872356470219.20994.9873000994.987013872251468995.90836.662500836.66013872556467931.90836.662500836.66013872544466812.50994.9873000994.98701387287246569801148.91360000013873538460972.40060001148.913013874388459138.301109.95556000013874639456867.30056000013875361454505.401148.91360001148.913013875456453188.901109.95556001109.955013875656452302.101109.9555600001-238757563875907451519451026.300600000上表为主线数据格式夏彬磊：用你这个表也行夏彬磊:JYNBi<XYIUMttCt)A4«9XrHiMU0)IiQOK9+4605923875120791456292.07028659'214,000KO÷CX)O.OOO3875»3.714453012.579o7(WQDDOZHIK96+495,9913875131.13545625821728659'2S4,HJDI38755855484530W.036YJOIKJOI38751719«456117*9GOIM040U.0093875664.731470903»112O5'14raj.oo9GQIHOW1K96+715.9913875W.1M456047.4M2855,24,220.000KJD2387440.749453149.432HH)IYJDI387W9.55854503251HY2BMhIT85»3575WW4745JW.60510229D67,95.526WY2noW1K97+W45373875SO.4«4SJ9J9.6O427509'4721128547YJDI3875447346453569.003YJD2KD23875407.06843866.566YH2«0*7195393875841268453525.5103N41237MIXXMYH2noCQ1K9S÷0M-5J73875417.6074M72O275274063220.000HJ03375875M45皿019HJ02KD33875428.126«3571983GQ2BK(M815.0e538759»W453604.569JM-0715/»526002HOHY2K98÷2M537J87MJ4214M50a½3275W,175220.000HJMM7601i57942482.599YJWYJD2387MU.323IUinxxiKWBK(HM5.4823876052J13455474.055M742515,121417003noYH2K98÷90.2843875626.20642884.2632832,623.747YJM38762173845X38.160HJD3HJD43875540.977452812.430YH3BKH269.4438763642545MC0.606738,4U3.966HY4no002K99+12a284387557J.M5452669.374282UU4,220.000HJ06«76426.428433191YJD4KD53875C05.69345252318ZD9043772435875490.959453479J54130,41,107.794YMnoZDK99+34a2843875620.466452454.485281312220.000/TNCXYMUOt)G04FKXY1M*U(t)QOCK04000.00037*7M1345344U1435519D<YJDS00Z×96H8592J87512ft7914K292.070286-smrZH1CK0-fWM3874948.8814W4M.226XA-ro8,<144YWFXHJDI38751M.650455151加2HJOI3875002.492455425.836KD5W1ZX95÷0,豹238751M.790455081.28628556*24*220.000HYICWM255513750299455425.44680.667ZDACYJOI3875JM5144MM9.557YJOIW511J8645J424.187W1ZK97÷f1O4.O613875389.6874M978.4K27512,411123.489VHICK044,K7387520ai56453447.6901542J17206A<HJ02387M96J494S»6462HJO2M7522M5745J4W.957QDGX001ZK98+024.08138万406的14M759.1W274<WJ9.6,220.000GQICwH5193387M76.754453472.9341931,2,80.667ZMIGXHJUM754176U4S¼12<7HJB375S40凶7645S4½564KJOI夏彬磊：就是需要自己算一下小刚：能否提供一下导入的数据格式的样表，计算我自己慢慢研究小刚：我要知道写那些参数，怎么写进去夏彬磊：针对圆曲线段，需要起始的方位角，与下一段的方位角的差值，有转角，有曲线长度，计算半径夏彬磊：在路易中，可以直接输入CurveDesignMethod这个命令夏彬磊:小刚：这个方法好，然后填表夏彬磊：输入第一个曲线的起始方位角，起点位置，后面把直线段，圆曲线段加上去就行了，按长度方式加进去夏彬磊：先计算圆曲线段的半径，缓和曲线与两端的曲线接的时候，一般都是曲线连续的，直接使用前后曲线的半径，以及本身曲线的长度就可以录入
