《C语言程序设计案例教程》（第2版）习题答案 北邮.docx
模块1习题答案一、选择题1.D2.A3.B4.C5.C6.C二、模仿编程1 .参考程序：#inc1ude"stdio.h"main()(f1oatarea,r=2.5,pi=3.1415926;area=pi*r*r;Printf("area=%fn",area);)2 .略。模块2习题答案一、选择题1.B2.A3.D4.A5.D6.A7.B8.A9.C10.D二、编程题1 .参考程序：#inc1ude"stdio.h"main()(f1oatarea,szr=2.5,pi=3.1415926;area=pi*r*r;s=2*pi*r;printf("area=%ns=%fn",area,s);)2 .参考程序：#inc1ude<std1ib.h>#inc1ude<stdio.h>main()(inta;intb;intc,d;a=1500zb=350;c=ab;商数d=a%b;余数Printf("商数为:%dn",c);Printf("余数为：dn",d);return0;)3 .参考程序：#inc1ude<stdio.h>#inc1ude<math.h>main()(f1oata,bzx,½z;a=2;b=3;x=3.5;y=2.6;z=(a+b)2+sqrt(a)-(y-x);printf("%f",z);)4 .略。模块3习题答案一、选择题1 .A2.C3.B4.D5.A6.C7.B8.D9.B10.D二、编程题1参考程序：#inc1ude<stdio.h>intmain()(inthours;f1oatwage;f1oatsa1ary;SCanf("%d%f",&hours,&wage);sa1ary=hours*wage*(1-0.1);printf("thesa1aryshou1dbe%fn",sa1ary);)2 .参考程序：#inc1ude<stdio.h>intmain()(f1oatf,c;Primf("输入华氏温度:n");scanf('"%f"f);c=5*(f-32)9;Printf("对应的摄氏温度是:%5.2fn"zc);)3 .参考程序：#inc1ude<stdio.h>#inc1ude<std1ib.h>intmain()(intnum,a,bzc;输入三位数Printf("请输入一个三位整数:n”)；SCanf("%d",&num);输出各位数a=num100;b=(num-a*100)10;c=(num-a*100-b*10);Printf("千位:%d,十位:%d,个位:%dn",a,b,c);return0;)模块4习题答案一、选择题1.B2.B3.D4.C5.A6.C7.C8.C9.A10.A二、编程题1参考程序：#inc1ude<stdio.h>intmain()(charc;c=getchar();读入一个字符，存储在c中。if(c=,a'c=,e'c=,i,c=,o'c='u'c=,A'c=,E'c=,c='O,c='U,)/判断是元音。printf(',%c是元音字母n",c);输出结果。e1se不是元音。printf(',%c不是元音字母n"Q;输出结果。return0;)2 .参考程序：inc1ude<stdio.h>intmain()intnum;Printfr请输入整数:")；scanf("%d,z&num);if(num%2=0)printf(,n%d是偶数,num);e1seprintf(,n%d是奇数，num);return0;)3 .答案略。4 .参考程序：#inc1ude<stdio.h>intmain()(intc,s;f1oatp,w,d,f;scanf("%f%f%d",&p,&w,&s);if(s>=3000)c=12;e1sec=s250;switch(c)(case0:d=0;break;case1:d=2;break;case2:d=5;break;case3:d=8;break;case4:d=10;break;case5:d=15;break;)f=p*w*s*(1-d100);printf("freight=%15.4fn"zf);)5 .参考程序：#inc1ude<stdio.h>#inc1ude<iostream.h>main()(intYear,Month,Day;cout<<,P1easeenterthecurrentdate(年月以空格分隔cin>>Year>>Month;whi1e(Month<=0Month>12)(CoUt<<"输入时间有误，请重新输入：cin>>Year>>Month;)Switch(Month)(case4:case6:case 8:case 9:case11:Day=30;break;case2:if(Year%400=0Year%4=0&&Year%100!=0)Day=29;e1seDay=28;break;defau1t:Day=31;)COUt<v”该月天数为:"<<Day<<"天")6.答案略。模块5习题答案一、选择题1.D2.C3.D4.C5.C6.B7.B8.D9.A10.A二、编程题1 .参考程序：inc1ude<stdio.h>main()(inti=1,sum=O,k=1;for(i=1;i<=101;i=i+2)(if(k%2=1)sum=sum+i;e1sesum=sum-i;k+;)Printf(,求和为:%d”,SUm);)2 .参考程序：#inc1ude<stdio.h>#inc1ude<math.h>main()(inti,t;intcount=0;intbf1ag=O;*break标记*/for(i=100;i<=200;i+)(bf1ag=O;for(t=2;t<=sqrt(i);t+)if(i%t=O)bf1ag=1;break;)if(!bf1ag)(printf("%4d"zi);+count;if(count%10=0)(count=0;printf("n");)printf("n");)3 .答案略。4 .答案略。5 .参考程序如下：#inc1ude<stdio.h>#inc1ude<std1ib.h>intmain()(inta,b,c;intcount=0;Printf("共有以下借法:n");for(a=1;a<=5;a+)/a,b,c,分别从一号书借到五号书(for(b=1;b<=5;b+)(for(c=1;c<=5;c+)(if(O!=(a-b)*(b-c)*(c-a)(count+;printf(',%d:%d%d%dt"zcount,a,b,c);if(0=count%3)(printf("n");)returnO;)6 .参考程序：#inc1ude<stdio.h>inta25;intmain()(a0=a1=1;for(inti=2;i<25;i+)ai=ai-1+ai-2;for(inti=0;i<25;i+)(printf("%3d',zai);if(i+1)%5=0)printf("n");)printf("n");return0;)模块6习题答案一、选择题1.B2.A3.D4.B5.B6.D7.C8.A二、编程题(略)1 .参考程序：#inc1ude<stdio.h>intmain()(doub1enum10;inti;doub1esum=O;Printf(”请连续输入十个实数:n“)；for(i=0;i<10;i+)(scanf("%1f",8tumi);)for(i=0;i<10;i+)(sum+=numi;Printf("第d个实数的和为名1fr,i+1,sum);)return0;2 .参考程序：#inc1ude<stdio.h>#inc1ude<string.h>main()(chara100;iti,j；gets(a);i=0;j=str1en(a)-1;whi1e(i<j)(if(ai=aU)(i+；j-；)e1sebreak;)if(i>=j)printf("YES.n");e1seprintf("NO.n");)3 .参考程序：#inc1ude<stdio.h>voiddec2bin(intn)(if(n>1)dec2bin(n2);printf("%d"zn%2);)intmain()(intx;scanf("%d',x);dec2bin(x);printf(',n");return0;)4 .答案略。5 .答案略。模块7习题答案一、选择题1.D2.C3.B4.C5.C6.A7.D8.A9.ACD10.C二、编程题1 .参考程序：inc1ude<stdio.h>intis_even(intn)(return!(n&Ox1);)intmain()(intn;scanf("%d''n);if(is_even(n)printf("偶数n");e1sePrintf(”奇数n");return0;)2 .参考程序：#inc1ude<stdio.h>voidfun(int*a,intIzint*bzint*n)(inti;*n=0;for(i=0;i<I;i+)if(ai%2=1)b(*n)+=ai;)intmain()(inta10=1,2,3,4,5,6,7,8,9,19;intb10;intn=0zi;fun(a,10,b,&n);for(i=0;i<n;i+)printf("%d",bi);return0;)3 .参考答案：#inc1ude<stdio.h>doub1emu1(intn)(inti;doub1es=1.0;for(i=1;i<=n;i+)returns;)intmain()(printf("c=6!+10!+22!=%gn",mu1(6)+mu1(10)+mu1(22);)
