大学科目数字电路习题参考答案.docx
第一章1.8(1)42.5(2)25.25(3)2.3125(4)0.78125(5)4.1251.11(100111001)8421(1000101Db(213)0(8B)h(10001101100)ex-3(100111100)54211.17(I)O1OO11O1OO11(2) IO111OIO1111(3) 1100111010110010(4)010111011010111011第二章2.1(1) A+C(2) AB+AC(3) 1(4) YZ+XZ(5) BC+ACD+ABD2.4(1) m(1,4,5,6)(2) m(0,1,7)(3) m(4,5,10,11,13,14)(4) m(0,1,4,5,6,7,8,9,10,11,12,13,14,15)2.5(1)M(O,2,4,6,7)(2)M(1,2,6,7)(3)M(10)(4)M(4,6,7,9)2.6(DB+AC(2)Z+Xy(3)BD+BD(4)XY+XZ+WYZ2.7(1) (A+B)(B+C)(2)(X+Z)(r+Z)(3)(B+D)(B+D)(4)(r+z)(iv+x)(x+y)2.8(1)AB+AB(2)WZ+WYZ(3)xP+xrz(4)c+a5+3O+N豆c+ab+d+5*注2.22(3)F=AC+AB=AC-i-AB=AC+AB2.24有一式错误2.36F=m(2,4,5,6)F=M(O,1,3,7)F=m(0,1,3,7)T=M(2,4,5,6)F*=m(0,4,6,7)F*=M(1,2,3,5)P=BCE÷ABDE+ACDE+BCDE+ACDE+ABCE+ABCDE图P2-9第三章O(b)(a),(b)都为尸=4B3.9P1=X1+X2+YiY2P2=+r2+X1X2P3=ABC(D+E)3.10三态输出高阻时，后一级门的输入端悬空，对TT1来说悬空为逻辑'1，P1=F(B+C)+F(AB+C+DE)P2=(AB+E+F-J)D+(AB+E+F+J+C)D3.11rc=P1=P2F=而尸1c=Ip=zP2=CAB+CDE4.1第四章(a)P=AOBC(b)P=AB+C(c)P=(A+8)CQ=P(d)P=(A+B)C(e)尸二(AB)CQ=(8+C)A(f)P=A+BQ=AB4.43,4,164.5P(A,B,C)=Zm(0,2,5)=ABC+ABC+ABC(a) _Q(AB,C)=£机(2,5,6)=ABC+ABC+ABC=BC+ABC(b) P1(B,C,D)=KZm(0,2,3)=ABCD+ABCD+ABCD=ABD+ABCP2(B,C,D)=入Zm(0,2,4,7)=ABCD+ABCD+ABCD=ABD+ACD+ABCD4.6P(AI,A0)=SZm(1,2)P2(A1,AO)=ST2(0,2)P1(AI,A0)=S71Zm(1,2)P2(1,AO)=SfiYn(O,2)O141144.20F1=W>(0,1,5,10,14,15),F2的MUX实现与F1完全一样A(1)尸=A”一(2)尸=A8CA=1BC=14.25方法一：用4-16线译码器实现：F1=Zm(1,2,4,7,8,11,13,14)产2=Z加(0,3,6,912,15)F3=Zm(3,9,12)F4=Zm(3,6,7,11,12,13,14,15)见右图，对应的输出端接4个与三该4个函数。BIN/HEX方法二：数据选择器实现:/=Z机(1,2,4,17,8,11,13,14)注（1）也可以用三个芹或门来实现即F=A8。(2/=Z皿0,3,6,9J2,15)(4)F=Zm(3,6,7,11,12,13,14,15)4.30F=ABD+ACD+BCD+BCD+ACD+ABDENO-O33EN012RABCDFOOOO0OOO11OO1O0OO11101000O1O1101101O111010000100111010110110110011101011101I11104.34ABCDFOOOO1000100010000110010000101101100O111010000100101010110110110001101011100I1111F='ABCD÷ABCD+ABCD+ABCD输入W,Z,Y,X依次改为X,W,Z,Y输出与门改为或门第五章(b)5.1(2)5.2(3)5.4t65.75.16(c),(d)5.18ENnD1nQnD.n1Qn+1OXOO0OX1111OXOO11X11(b)2,+1=D1=JQn+KQn=END1+ENQn=ENDI(Q"+Q")+ENQn可得：J=ENDIK=ENDID=A+8+3+C+Q+C+A+B)2CPMD H- S D5 2 5.IQiQ2n+,=01；QQ2n+2=106.12有两个循环序列，长度分别是1和15,解决自启动问题参考如下图所示:状态转换表（1）SQ3Q2QiQo'1Q3Q:2Q1Q0n+1100010011300110111701111111151111111014111011011311011010101010010150101101111101101106011011001211001001910010010200100100401001000810000001-6.18M=13状态转换表SQ3Q2Q1QonQ3Q2Q1Q0n+100000000100010010200100011300110100401000101501010110601100111701111000810001001910011010101010101111101111001211()Q000100()0OV7)001遒S=13状态仅为过渡状态6.20Q2、Q3、P波形适宜于作为分频波形输出6.24SQ3Q2Q1QonQ3Q2Q1Q0n+1810000111*7O1110110601100101501010100401000011300110010200100001100010000000001000M=9电路为减1模式状态转换表状态转换图M=I时，电路为加1模式，模M=5SQ3Q2Q1Q0nQ3Q2Q1Qn+1300110100-40100010150101011060110O1117O11100111状态转换表状态转换图SQ3Q2Q1Q0nQ3Q2Q1Q0n+130011001OF20010000110001000000000001-jM=OW,电路为减1模式，模M=4状态转换表M=O,递减，模为6；M=1,递加，模为56.261DQ2Q3(a)741S196波形图如卜J23456789CPj1r1mrw1r1nj11D-jQO一-Qi_Q2_Q3b
