5G工程师常见面试问答.docx
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1、一、常见5G面试问题汇总1、5G峰值速率的计算公式是什么?子载波间隔为30khz,上下行配比为3:1,下行使用256QAM时,峰值速率约为 273*12*14*2*8*0.925*0.74*4*0.7*1000/109=1.4Gbps2、为什么SCS为30khz时,5G下行满灌包时PDSCH RB达不到273 ?主要是由于SSB占用了 240个子载波合计20个RB,在含有SSB的时隙对应的PDSCH RB少于273 (实际为225个),不含有SSB的时隙对应的PDSCH RB为273,所以平均之下少于273RB。3、广电700Mhz频段能用Massive MIMO吗?天线阵子之间的距离要求大于
2、半波长(波长与频率成反比),假如700Mhz应用Massive MIMO,其天线尺寸要比C波段天线阵面大许多,实施安装部署很难,所以综合考虑之下不用。4、5GNR定义的频谱中SUL是做什么用的?由于NR在C-Band上均使用TDD, gNodeB下行功率(200w)远大于手机功率(0.2w),大规模天线波束赋形、CRS-Free等技术,导致C-Band上下行掩盖不平衡,上行掩盖受限成为5G部署掩盖范围的瓶颈。因此提出了 SUL应用在上下行解耦方案中,通过采纳低频的SUL部署FDD LTE (仅含有上行)进行上行补充掩盖来解决上行掩盖受限的问题。5、5G NR中有哪些测量大事,测量报告中的RSR
3、P如何计算?在38.331/36.331中第五章有介绍测量大事的类型。Event TypeDescriptionEvent AlServing becomes better than thresholdEvent A2Serving becomes worse than thresholdEvent A3Neighbour becomes offset better than servingEvent A4Neighbour becomes better than thresholdEvent A5Serving becomes worse than threshold 1 and neigh
4、bour becomes better than threshold2Event A6Neighbour become offset better than S Cell (This event is introduced in Release 10 for CA)Event BlInter RAT neighbour becomes better than thresholdEvent B1-NRNR neighbour becomes better than thresholdEvent B2Serving becomes worse than threshold 1 and inter
5、RAT neighbour becomes better thanthreshold2Event B2-NRServing becomes worse than threshold 1 and NR neighbour becomes better than threshold2Event ClCSI-RS resource becomes better than thresholdEvent C2CSI-RS resource becomes offset better than reference CSI-RS resourceEvent WlWLAN becomes better tha
6、n a thresholdEvent W2All WLAN inside WLAN mobility set becomes worse than threshold 1 and a WLAN outside WLANmobility set becomes better than threshold2Event W3All WLAN inside WLAN mobility set becomes worse than a thresholdEvent VIThe channel busy ratio is above a thresholdEvent V2The channel busy
7、ratio is below a thresholdEvent HlThe Aerial UE height is above a thresholdEvent H2The channel busy ratio is below a threshold .rrr.那么大事的触发在于测量的信号是否超过了某一门限。Neighbour CellServing Cell/P Celltime,hysterisisoffset-一前景里讫LTE实际值为MR上报值一140,而NR则为MR上报值-156。假设NR, MR中上报的RSRP为50,则实际值则为50-156二-106为m。MR中上报的RSRP为5
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