非线性解析概要-Abaqus 6.9 Nonlinearity (1).docx
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1、 NonlinearityThis chapter discusses nonlinear structural analysis in Abaqus. The differencesbetween linear and nonlinear analyses are summarized below.Linear analysisAll the analyses discussed so far have been linear: there is a linear relationshipbetween the applied loads and the response of the sy
2、stem. For example, if a linearspring extends statically by 1 m under a load of 10 N, it will extend by 2 m when a loadof 20 N is applied. This means that in a linear Abaqus/Standard analysis the flexibilityof the structure need only be calculated once (by assembling the stiffness matrix andinverting
3、 it). The linear response of the structure to other load cases can be found bymultiplying the new vector of loads by the inverted stiffness matrix. Furthermore, thestructures response to various load cases can be scaled by constants and/orsuperimposed on one another to determine its response to a co
4、mpletely new loadcase, provided that the new load case is the sum (or multiple) of previous ones. Thisprinciple of superposition of load cases assumes that the same boundary conditionsare used for all the load cases.Abaqus/Standard uses the principle of superposition of load cases in linear dynamics
5、simulations, which are discussed in Chapter 7, “Linear Dynamics.”Nonlinear analysisA nonlinear structural problem is one in which the structures stiffness changes as itdeforms. All physical structures are nonlinear. Linear analysis is a convenientapproximation that is often adequate for design purpo
6、ses. It is obviously inadequatefor many structural simulations including manufacturing processes, such as forging orstamping; crash analyses; and analyses of rubber components, such as tires or enginemounts. A simple example is a spring with a nonlinear stiffening response (see Figure8-1).Figure 8-1
7、 Linear and nonlinear spring characteristics.ForceForceDisplacementLinear spring.DisplacementNonlinear spring.Stiffness is not constantStillness is constantSince the stiffness is now dependent on the displacement the initial flexibility can nolonger be multiplied by the applied load to calculate the
8、 springs displacement for anyload. In a nonlinear implicit analysis the stiffness matrix of the structure has to beassembled and inverted many times during the course of the analysis, making it muchmore expensive to solve than a linear implicit analysis. In an explicit analysis theincreased cost of
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